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0.75x^2+15x-4.8=0
a = 0.75; b = 15; c = -4.8;
Δ = b2-4ac
Δ = 152-4·0.75·(-4.8)
Δ = 239.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{239.4}}{2*0.75}=\frac{-15-\sqrt{239.4}}{1.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{239.4}}{2*0.75}=\frac{-15+\sqrt{239.4}}{1.5} $
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